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If the dimension of a physical quantity is given by \( \left[M^{a} L^{b} T^{c}\right] \) then the physical quantity will be
- acceleration, if \( a=1, b=-1, c=-2 \)
- velocity, if \( a=1, b=0, c=-1 \)
- pressure, if \( a=1, b=-1, c=-2 \)
- force, if \( a=0, b=-1, c=-2 \)
Correct answer: pressure, if \( a=1, b=-1, c=-2 \)
Solution
Pressure has dimensions of force per unit area, so its dimensional formula is \([M^1L^{-1}T^{-2}]\). This matches \(a=1, b=-1, c=-2\), so the correct choice is pressure.
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