Exams › NEET › Physics

Dimensions of resistance in an electrical circuit, in terms of dimension of mass [M], of length [L], of time [T] and of current [I], would be:

1. [ML²T⁻³I⁻²]
2. [ML²T⁻³I⁻¹]
3. [ML²T⁻³I⁻²]
4. [ML²T⁻³I⁻¹]

Correct answer: [ML²T⁻³I⁻²]

Solution

The formula for resistance is R = V/I, where V (voltage) has dimensions [ML²T⁻³I⁻¹] and I (current) has dimensions [I]. Dividing these gives the dimensions of resistance as [ML²T⁻³I⁻²].

Related NEET Physics questions

• \( \mathbf{1}^{o} \boldsymbol{A} \) is
• Which of the following is different from the rest?
• Assertion nm is not same as mN Reason \( \ln m=10^{-9} m \operatorname{and} 1 m N=10^{-3} N \)
• If the dimension of a physical quantity is given by \( \left[M^{a} L^{b} T^{c}\right] \) then the physical quantity will be
• In a new system, unit of mass is \( 10 \mathrm{kg} \) unit of length is \( 5 \mathrm{m} \) and unit of time is 10s. Then in the new system 5N is equal to :
• A cube has a side of length \( 2.342 m \). The surface area and volume in correct significant figures are respectively:

⚔️ Practice NEET Physics free + battle 1v1 →