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The dimension of ½ε₀E², where ε₀ is permittivity of free space and E is electric field, is:
- [ML²T⁻²]
- [ML⁻¹T⁻²]
- [ML²T⁻¹]
- [ML⁻¹T⁻¹]
Correct answer: [ML²T⁻²]
Solution
The term ½ε₀E² represents energy density. The dimension of energy is [ML²T⁻²], and since it is per unit volume, the dimension remains [ML²T⁻²].
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