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The ionisation energy of hydrogen atom is 13.6 eV, the ionisation energy of helium atom would be
- 13.6 eV
- 27.2 eV
- 6.8 eV
- 54.4 eV
Correct answer: 54.4 eV
Solution
The ionisation energy of a hydrogen-like atom is proportional to the square of its atomic number (Z). For helium (Z=2), the ionisation energy is 13.6 × Z² = 13.6 × 4 = 54.4 eV.
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