Exams › NEET › Physics
The resistance of an ammeter is 13 Ω and its scale is graduated for a current upto 100 amps. After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto 750 amps by this meter. The value of shunt-resistance is
- 2 Ω
- 0.2 Ω
- 2 kΩ
- 20 Ω
Correct answer: 0.2 Ω
Solution
The shunt resistance is connected in parallel with the ammeter. Using the formula for parallel resistance, Rs = (Ra * I1) / (I2 - I1), where Ra = 13 Ω, I1 = 100 A, and I2 = 750 A, we calculate Rs = (13 * 100) / (750 - 100) = 0.2 Ω.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →