Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by i = E / (R + r). In first case, 2 = E / (2 + r). In second case, 0.5 = E / (9 + r). From (1) & (2), 4 + 2r = 4.5 + 0.5r. ⇒ 1.5r = 0.5 ⇒ r = 1/3 Ω.

Question

Accepted Answer

From (1) & (2), 4 + 2r = 4.5 + 0.5r. ⇒ 1.5r = 0.5 ⇒ r = 1/3 Ω.. The correct answer is D because it provides the final calculation and result for the internal resistance, r, based on the given equations. The other options are intermediate steps or statements.

Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by i = E / (R + r). In first case, 2 = E / (2 + r). In second case, 0.5 = E / (9 + r). From (1) & (2), 4 + 2r = 4.5 + 0.5r. ⇒ 1.5r = 0.5 ⇒ r = 1/3 Ω.

Solution

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