Correct answer: 0.5 Ω
In a metre-bridge, the balancing condition is given by the ratio of resistances being equal to the ratio of the lengths. Here, the balancing length is 20 cm, so the other length is 100 - 20 = 80 cm. Using the formula R1/R2 = L1/L2, where R1 is the unknown resistance and R2 is 1 Ω, we get R1 = (L1/L2) * R2 = (20/80) * 1 = 0.25 Ω.