Exams › NEET › Physics
A 5–ampere fuse wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is:
- 0.04 ohm
- 0.2 ohm
- 5 ohm
- 0.4 ohm
Correct answer: 0.2 ohm
Solution
The power dissipated in the fuse wire is given by P = I²R. Substituting P = 1 W and I = 5 A, we get R = P/I² = 1/(5²) = 0.2 ohm.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →