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Two wires are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5 Ω. The power loss in the wires is:
- 19.2 W
- 19.2 kW
- 12.2 kW
- 19.2 J
Correct answer: 19.2 kW
Solution
The total resistance of the wire is R = 0.5 Ω/km × 150 km = 75 Ω. The total voltage drop is V = 8 V/km × 150 km = 1200 V. Power loss is given by P = V²/R = (1200)²/75 = 19.2 kW.
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