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Resistances, each of r ohm, when connected in parallel give an equivalent resistance of R ohm. If these resistances were connected in series, the combination would have a resistance in ohms, equal to
- nr
- n²R
- R/n²
- R/n
Correct answer: nr
Solution
In parallel, the equivalent resistance is given by R = r/n. When connected in series, the total resistance is nr, as the resistances simply add up. Thus, the correct answer is nr.
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