StreakPeaked· Practice

ExamsNEETPhysics

The escape velocity on the surface of earth is 11.2 km/s. What would be the escape velocity on the surface of another planet of the same mass but 1/4 times the radius of the earth?

  1. 22.4 km/s
  2. 44.8 km/s
  3. 5.6 km/s
  4. 11.2 km/s

Correct answer: 44.8 km/s

Solution

Escape velocity is proportional to the square root of the planet's radius for a given mass. Since the radius is reduced to 1/4, the escape velocity increases by a factor of √4 = 2. Thus, the new escape velocity is 11.2 × 2 = 22.4 km/s.

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