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From conservation of linear momentum, m1v1 + m2v2 = 0. If m1 = 12 kg and m2 = 6 kg, what is v2?

1. -9 ms^-1
2. -6 ms^-1
3. -3 ms^-1
4. -12 ms^-1

Correct answer: -3 ms^-1

Solution

Using conservation of linear momentum, m1v1 + m2v2 = 0. Rearranging, v2 = -(m1v1)/m2. Substituting m1 = 12 kg, m2 = 6 kg, and assuming v1 = 3 m/s (as it is not given but implied for calculation), v2 = -(12 × 3)/6 = -6 m/s.

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