StreakPeaked· Practice

ExamsNEETPhysics

Force due to friction = kinetic energy. μ mg s = 1/2 mv^2.

  1. (a) μ mg s = 1/2 mv^2
  2. (b) Here, v = 72 km/h = 72000 / 60 x 60 = 20 m/s
  3. (c) μ = s / 1/2 m
  4. (d) All of the above

Correct answer: (a) μ mg s = 1/2 mv^2

Solution

Option (a) is correct because it correctly equates the work done by friction (μmg * s) to the kinetic energy (1/2 mv^2). The other options contain incorrect or incomplete expressions.

Related NEET Physics questions

⚔️ Practice NEET Physics free + battle 1v1 →