Exams › NEET › Physics
If k be the spring constant, then:
- U = 1/2 k × x² = 2k
- Ufinal = 1/2 k × x(10)² = 50k
- New K.E., E' = E' + 3E = 4E
- p' / p = √(2m × 4E / 2mE') = 2
Correct answer: p' / p = √(2m × 4E / 2mE') = 2
Solution
Option D is correct because the ratio of momentum (p'/p) is derived using the relationship between kinetic energy and momentum, where p = √(2mE). The ratio simplifies to 2 as given.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →