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Two bodies of masses m and 4m are moving with equal K.E. The ratio of their linear momenta is

1. 4 : 1
2. 1 : 1
3. 1 : 2
4. 1 : 4

Correct answer: 1 : 2

Solution

Kinetic energy is given by K.E. = p²/2m, where p is momentum. For equal K.E., p ∝ √m. Thus, the ratio of their momenta is √m : √(4m) = 1 : 2.

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