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When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be:

1. 25 U
2. U/5
3. 5 U
4. 10 U

Correct answer: 25 U

Solution

The potential energy stored in a spring is proportional to the square of the extension (U ∝ x²). If the extension increases from 2 cm to 10 cm, the ratio of extensions is 10/2 = 5. Therefore, the potential energy increases by a factor of 5² = 25, making the new potential energy 25U.

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