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If friction is present, then maximum safe speed on a banked frictional road is given by:

1. v = √Rg
2. v = √(Rg(1 + tan θ)/(1 − tan θ))
3. v = √(Rg tan θ)
4. v = √(Rg(1 − tan θ)/(1 + tan θ))

Correct answer: v = √(Rg(1 + tan θ)/(1 − tan θ))

Solution

The maximum safe speed on a banked road with friction is derived by considering the forces acting on the vehicle, including friction, normal force, and gravitational force. The correct formula is v = √(Rg(1 + tan θ)/(1 − tan θ)).

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