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What will be the maximum speed of a car on a road turn of radius 30 m if the coefficient of friction between the tyres and the road is 0.4 (Take g = 9.8 m/s²)?
- 10.84 m/s
- 9.84 m/s
- 8.84 m/s
- 6.84 m/s
Correct answer: 10.84 m/s
Solution
The maximum speed of a car on a turn is given by the formula v = √(μrg), where μ is the coefficient of friction, r is the radius, and g is the acceleration due to gravity. Substituting the values: v = √(0.4 × 30 × 9.8) = √(117.6) ≈ 10.84 m/s.
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