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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:

1. Mv newton
2. 2 Mv newton
3. Mv/2 newton
4. zero

Correct answer: Mv newton

Solution

The force required is equal to the rate of change of momentum. Since sand is being added at a rate of M kg/s and the velocity of the belt is v m/s, the force is F = Mv.

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