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A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N. What is the maximum speed with which the ball can be moved?
- 14 m/s
- 3 m/s
- 5 m/s
- 3.92 m/s
Correct answer: 3.92 m/s
Solution
The maximum tension in the string is given as 25 N. Using the formula for centripetal force, T = mv²/r, where T is the tension, m is the mass, v is the speed, and r is the radius of the circle, we solve for v: v = √(T * r / m). Substituting T = 25 N, r = 1.96 m, and m = 0.25 kg, we get v = √(25 * 1.96 / 0.25) = 3.92 m/s.
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