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ExamsNEETPhysics

A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N. What is the maximum speed with which the ball can be moved?

  1. 14 m/s
  2. 3 m/s
  3. 5 m/s
  4. 3.92 m/s

Correct answer: 3.92 m/s

Solution

The maximum tension in the string is given as 25 N. Using the formula for centripetal force, T = mv²/r, where T is the tension, m is the mass, v is the speed, and r is the radius of the circle, we solve for v: v = √(T * r / m). Substituting T = 25 N, r = 1.96 m, and m = 0.25 kg, we get v = √(25 * 1.96 / 0.25) = 3.92 m/s.

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