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Let the body fall through the height of the tower in nth seconds. From, Dₙ = u + (a/2)(2n−1), we have, total distance travelled in last 2 seconds of fall is D = D₁ + D₍ₙ₋₁₎. Which of the following is correct?

1. x(4) = g/2(2×4−1)
2. x(5) = g/2(2×5−1)
3. x(4) = g/2(2×4−1) = 7
4. x(5) = g/2(2×5−1) = 9

Correct answer: x(5) = g/2(2×5−1)

Solution

The formula Dₙ = u + (a/2)(2n−1) is used to calculate the distance traveled in the nth second. For x(5), substituting n = 5, u = 0 (free fall), and a = g, we get x(5) = g/2(2×5−1) = g/2(9). This matches option B.

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