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A body dropped from top of a tower fell through 40 m during the last two seconds of its fall. The height of tower is (g = 10 m/s^2)

1. (a) 60 m
2. (b) 45 m
3. (c) 80 m
4. (d) 50 m

Correct answer: (c) 80 m

Solution

Using the equation of motion, the distance covered in the last two seconds is given by s = u*t + (1/2)*g*t^2. Here, u = 0 (initial velocity), g = 10 m/s², and t = 2 s. Solving for the total height of the tower, we find it to be 80 m.

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