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A stone released with zero velocity from the top of a tower, reaches the ground in 4 sec. The height of the tower is (g = 10 m/s^2)

1. (a) 20 m
2. (b) 40 m
3. (c) 80 m
4. (d) 160 m

Correct answer: (c) 80 m

Solution

The stone is in free fall, so we use the equation of motion: h = (1/2)gt^2. Substituting g = 10 m/s² and t = 4 s, we get h = 0.5 × 10 × (4)^2 = 80 m.

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