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If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s, it covers a distance of

1. 2880 m
2. 1440 m
3. 20 m
4. 400 m

Correct answer: 1440 m

Solution

The car's initial velocity (u) is 0 m/s, final velocity (v) is 144 km/h = 40 m/s, and time (t) is 20 s. Using the equation of motion, s = ut + (1/2)at², we first calculate acceleration (a) using v = u + at, giving a = 2 m/s². Substituting into the equation for s, we get s = 0 + (1/2)(2)(20)² = 400 m.

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