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If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is

1. (a) (u + g t) t
2. (b) u t
3. (c) 1/2 g t^2
4. (d) u t - 1/2 g t^2

Correct answer: (d) u t - 1/2 g t^2

Solution

During the last t seconds of ascent, the ball's velocity decreases due to gravity. The distance covered is given by the equation s = ut - 1/2 g t^2, where u is the initial velocity and g is the acceleration due to gravity.

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