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If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be:

1. 4%
2. 6%
3. 8%
4. 2%

Correct answer: 8%

Solution

The volume of a sphere is proportional to the cube of its radius (V ∝ r³). Therefore, the percentage error in volume is three times the percentage error in radius, i.e., 3 × 2% = 6%.

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