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A particle moves in a circular path. If \(\omega\) is the angular velocity vector and \(\vec r\) is the position vector of the particle from the centre, which expression correctly gives the linear velocity \(\vec v\) of the particle?
- \(\vec v = \vec r \cdot \omega\)
- \(\vec v = \omega \cdot \vec r\)
- \(\vec v = \omega \times \vec r\)
- \(\vec v = \vec r / \omega\)
Correct answer: \(\vec v = \omega \times \vec r\)
Solution
For a particle in circular motion, the instantaneous linear velocity is given by the cross product of angular velocity and position vector. This ensures the velocity is tangential to the path and perpendicular to the radius vector.
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