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Two racing cars of masses \(m_1\) and \(m_2\) travel in circles of radii \(r_1\) and \(r_2\), respectively. Both complete one full revolution in the same time period \(t\). What is the ratio of the angular speed of the first car to the second car?
- m1: m2
- r1: r2
- 1: 1
- m1*r1: m2*r2
Correct answer: 1: 1
Solution
Angular speed is \(\omega = \frac{2\pi}{T}\). Since both cars take the same time period \(t\) for one revolution, their angular speeds are equal, so the ratio is 1:1.
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