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Two conductors each of length \( 12 m \) lie parallel to each other in air. The centre to centre distance between the two conductors is \( 15 \times 10^{-2} m \) and the current in each conductor is \( 300 A \). The force in newton tending to pull the conductors together is:

1. \( 14.4 N \)
2. \( 1.44 N \)
3. \( 144 N \)
4. \( 0.144 N \)

Correct answer: \( 1.44 N \)

Solution

For two parallel conductors, the attractive force is proportional to \(I_1 I_2 L / d\). Substituting the given values into the standard formula gives \(1.44\,\text{N}\), so the conductors tend to pull together with that force.

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