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Calculate the heat energy required to convert completely \( 10 \mathrm{kg} \) of water at \( 50^{\circ} \mathrm{C} \) into steam at \( 100^{\circ} \mathrm{C} \), given that the specific heat capacity of water is \( 4200 J /\left(k g^{\circ} C\right) \) and the specific latent heat of vaporisation of water is \( 2260 k J / k g \)
- 30451 KJ
- 60562 KJ
- 72103 KJ
- 24700 KJ
Correct answer: 24700 KJ
Solution
First, the 10 kg of water must be heated from 50°C to 100°C, which takes Q = mcΔT. Then it must be converted to steam at 100°C using the latent heat of vaporisation; adding both parts gives the total energy.
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