Exams › NEET › Physics

A 50 gram bead slides on a frictionless wire as shown above. At what point on the wire will the bead come to a complete stop? The initial speed at \( C \) is \( \sqrt{2 g h} \)

1. Point \( A \)
2. Point B
3. Point \( c \)
4. Point D E. Point E

Correct answer: Point D E. Point E

Solution

Because the wire is frictionless, mechanical energy is conserved. The bead’s initial kinetic energy at C is \(\tfrac12 mv^2 = \tfrac12 m(2gh)=mgh\), so it will come to rest after rising by a vertical height of \(h\) above C.

Related NEET Physics questions

• \( g c m s^{-2} \) is also known as
• The coefficient of limiting friction between the surfaces of contact is the ratio of the \( \ldots \). friction to the normal reaction
• Point where whole weight of body acts vertically is called
• In a physical balance working on the principle of moments, when \( 5 \mathrm{mg} \) weight is placed on the left plan, the beam becomes horizontal. Both the empty pans of the balance are of equal mass. Which of the following statements is correct?
• A box is placed on an inclined plane and has to be pushed down. The angle of inclination is :
• A rubber ball of mass \( 4 \mathrm{kg} \) has the same diameter as a plastic ball of mass 0.5 kg. Both the balls are dropped simultaneously from the roof of a building.When they are \( 8 \mathrm{m} \) above the ground,they have the same

⚔️ Practice NEET Physics free + battle 1v1 →