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A body of mass 2 kg is thrown up vertically with K.E. of 490 joules. If the acceleration due to gravity is 9.8 2 / s m , then the height at which the K.E. of the body becomes half its original value is given by
- 50 m
- 12.5 m
- 25 m
- 10 m
Correct answer: 12.5 m
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