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A force acts on a 30 gm particle in such a way that the position of the particle as a function of time is given by 3 2 4 3 t t t x , where x is in metres and t is in seconds. The work done during the first 4 seconds is
- 5.28 J
- 450 Mj
- 490 mJ
- 530 mJ
Correct answer: 5.28 J
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