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A 50 V battery is connected across a 10 resistor. The current is 4.5 A. The internal resistance of the battery is
- Zero
- 0.5 ohm
- 1.1 ohm
- 5.0 ohm
Correct answer: 1.1 ohm
Solution
For a cell, the total resistance in the circuit is emf/current. Here, total resistance = 50/4.5 11.11 . Subtracting the external 10 gives internal resistance 1.1 .
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