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If three resistors of resistance 2 a9, 4 a9 and 5 a9 are connected in parallel, then the total resistance of the combination is

1. 19/20 a9
2. 20/19 a9
3. 10/19 a9
4. 19/10 a9

Correct answer: 19/20 a9

Solution

For resistors in parallel, 1/R = 1/2 + 1/4 + 1/5 = 19/20. Therefore, R = 20/19 a9? Wait, the reciprocal sum itself is 19/20, so the equivalent resistance is 20/19 a9. The correct option is 20/19 a9.

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