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Three resistors, each of 1 a9, are joined in parallel. Three such combinations are then connected in series. The resultant resistance is

1. 9 a9
2. 3 a9
3. 1 a9
4. 3 1 a9

Correct answer: 1 a9

Solution

Three 1 a9 resistors in parallel have equivalent resistance 1/3 a9. Three such groups in series add up to 1 a9. Therefore, the resultant resistance is 1 a9.

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