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There are 8 equal resistances \(R\). Two are connected in parallel, and such four groups are connected in series. The total resistance of the system will be

1. \(R/2\)
2. \(2R\)
3. \(4R\)
4. \(8R\)

Correct answer: \(2R\)

Solution

Each pair of resistors in parallel has equivalent resistance \(R/2\). There are four such groups connected in series, so the total resistance is \(4 \times (R/2) = 2R\).

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