The power dissipated in the circuit shown in the figure is 30 W. The value of $R$ is:
20 Ω
15 Ω
10 Ω
30 Ω
Correct answer: 10 Ω
Solution
The total power dissipated is related to the circuit current and equivalent resistance by $P=I^2R_{eq}$ or $P=V^2/R_{eq}$. Using the resistance combination in the figure, the value of $R$ comes out to be $10\,\Omega$.