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A mass \(m\) is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

1. inclined at an angle of \(60^\circ\) from the vertical
2. the mass is at the highest point
3. the wire is horizontal
4. the mass is at the lowest point

Correct answer: the mass is at the lowest point

Solution

In vertical circular motion, tension is maximum at the lowest point because it must provide centripetal force and also balance the weight. Therefore, the wire is most likely to break there.

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