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A car of mass \(m\) is moving on a level circular track of radius \(R\). If \(\mu_s\) represents the static friction between the road and the tyres of the car, the maximum speed of the car in circular motion is given by:
- \(\mu_s \sqrt{Rg}\)
- \(\sqrt{Rg/\mu_s}\)
- \(\mu_s \sqrt{Rg/m}\)
- \(\sqrt{Rg\mu_s}\)
Correct answer: \(\mu_s \sqrt{Rg}\)
Solution
The maximum centripetal force on a level road is provided by static friction, \(\mu_s mg\). Equating this to \(mv^2/R\) gives \(v_{\max} = \sqrt{\mu_s g R}\).
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