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A stone of mass 1 kg is tied to a string of length \(\frac{10}{3}\) m and rotated in a vertical circle. If the ratio of maximum tension to minimum tension in the string is 4, the speed of the stone at the highest point of the circular path is: \((g = 10\,\text{m/s}^2)\)
- 20 m/s
- 10\sqrt{3} m/s
- 5\sqrt{2} m/s
- 10 m/s
Correct answer: 10 m/s
Solution
In vertical circular motion, tension is maximum at the bottom and minimum at the top. Using \(T_b - T_t = 2mg\) and the given ratio \(T_b/T_t = 4\), we get the tension values and then use the top-point equation \(T_t + mg = mv^2/r\).
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