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A stone of mass 0.5 kg tied to a string of length 1 m is moving in a circular path with a speed of 4 m/s. The tension in the string is:

1. 2
2. 8
3. 0.2
4. 0.8

Correct answer: 8

Solution

The tension in the string provides the centripetal force needed for circular motion. Using $T=\frac{mv^2}{r}$ with $m=0.5$ kg, $v=4$ m/s, and $r=1$ m gives $T=8$ N.

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