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The centre of mass of the shaded portion of the disc is: (The mass is uniformly distributed in the shaded portion)

1. R 20 to the left of A
2. R 12 to the left of A
3. R 20 to the right of A
4. R 12 to the right of A

Correct answer: R 20 to the left of A

Solution

For a uniformly distributed shaded disc segment, the centre of mass is found by balancing the shaded area about the reference point. From the given figure, the resultant position is \(R/20\) to the left of A.

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