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The missing particle in the reaction: \( \underset{99}{253} \boldsymbol{E} \boldsymbol{s}+_{2}^{4} \boldsymbol{H} \boldsymbol{e} \rightarrow_{101}^{256} \boldsymbol{M} \boldsymbol{d}+ \)

1. deuteron
2. proton
3. neutron
4. \( \beta \) - particle

Correct answer: deuteron

Solution

The total mass number goes from 253 + 4 to 256, so the missing particle must have mass number 1. The atomic number goes from 99 + 2 to 101, so the missing particle must also have charge 0, which matches a neutron.

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