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Find out the missing particle in the following nuclear reaction? \( _{1}^{2} \boldsymbol{H}+_{29}^{63} \boldsymbol{C u} \rightarrow_{30}^{64} \boldsymbol{Z} \boldsymbol{n}+(?) \)

1. Proton
2. Neutron
3. Electron
4. Positron E . Deuteron

Correct answer: Neutron

Solution

Balance the reaction by comparing total mass numbers and atomic numbers. The left side has mass number 65 and charge 30; since zinc-64 on the right has charge 30, the missing particle must have mass number 1 and charge 0, which is a neutron.

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