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The average half-cycle value of a sine wave with a \( 40 V \) peak is
- \( 25.48 V \)
- \( 6.37 V \)
- \( 14.14 V \)
- \( 50.96 V \)
Correct answer: \( 25.48 V \)
Solution
The average value over one half-cycle of a sine wave is \(\frac{2V_m}{\pi}\). With a peak value of 40 V, this gives \(\frac{2\times 40}{\pi} \approx 25.48\) V. That matches the correct option.
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