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The iodine atom has 53 electrons arranged as 2, 8, 18, 18, 7. Determine the orbital radius for the fifth energy level (n = 5).

1. 0.53 × 10⁻¹⁰ × n² / Z
2. 0.53 × 10⁻¹⁰ × 5² / 53
3. 2.5 × 10⁻¹¹ m
4. None of these

Correct answer: 0.53 × 10⁻¹⁰ × 5² / 53

Solution

The radius of an orbit in a hydrogen-like atom is given by r = 0.53 × 10⁻¹⁰ × n² / Z. Substituting n = 5 and Z = 53, the correct expression is 0.53 × 10⁻¹⁰ × 5² / 53.

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