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Given that Q1 equals 4 times Q2, it follows that K1Δt/L equals 4 times K2Δt/L. Which of the following relationships is correct?

1. K1A1 is 4 times K2A2
2. K1A1 equals K2A2
3. K1A1 is twice K2A2
4. K1A1 is 8 times K2A2

Correct answer: K1A1 is 4 times K2A2

Solution

The given equation K1Δt/L = 4K2Δt/L simplifies to K1A1 = 4K2A2, as the terms Δt and L cancel out. This matches option A.

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