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If the momentum of the first fragment is m × 21 = 21m, and the momentum of the second fragment is also m × 21 = 21m, the combined momentum is calculated as √((m × 21)^2 + (m × 21)^2). This combined momentum equals the momentum of the third fragment, which is 21√2 m. What is the velocity (v) of the third fragment?

1. The momentum of the first fragment is m × 21 = 21m.
2. The momentum of the second fragment is m × 21 = 21m.
3. The combined momentum is √((m × 21)^2 + (m × 21)^2).
4. The velocity (v) of the third fragment is 7√2 m/sec.

Correct answer: The velocity (v) of the third fragment is 7√2 m/sec.

Solution

The final velocity of the third part is calculated as v = 7√2 m/s, which matches option D. This is derived from the conservation of momentum and the given data.

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