Exams › NEET › Physics

The velocity of a particle is defined as v = ds/dt = 3t² - 12t + 3. Its acceleration, given by a = dv/dt, is calculated as a = 6t - 12. Setting a = 0, we find t = 2 seconds. At this time, the velocity of the particle is v = 3 × 2² - 12 × 2 + 3 = -9 m/s. Which of the following represents the correct expression for velocity?

1. v = ds/dt = 3t² - 12t + 3
2. v = ds/dt = 3t² - 12t + 6
3. v = ds/dt = 3t² - 12t + 9
4. v = ds/dt = 3t² - 12t + 12

Correct answer: v = ds/dt = 3t² - 12t + 3

Solution

The given solution uses the equation v = 3t² - 12t + 3 to calculate velocity and acceleration. The calculations match this equation, confirming it as correct.

Related NEET Physics questions

• In the equation of motion, \( \boldsymbol{S}=\boldsymbol{u} \boldsymbol{t}+ \) \( 1 / 2 a t^{2}, \) S stands for
• A body is accelerated by applying a force of 30 N. The change in the momentum of the body after 2 sec is?
• A passenger in moving train tosses a coin which falls behind him. It means that the motion of the train is
• From the displacement-time graph shown here, find the velocity of the body as it moves from \( A \) to \( B \)
• The distance of a particle as a function of time is shown below. The graph indicates that
• Whenever an object moves with a constant speed, its distance - time graph is a

⚔️ Practice NEET Physics free + battle 1v1 →